## SetFxOpPos

### Introduced

v3.0

### Description

Sets the position of an FxOperator in the FxTree.

### Scripting Syntax

    SetFxOpPos( [FxOp], [x], [y] );

### Parameters

Parameter | Type | Description
--- | --- | ---
FxOp | String or FxOperator | Object pointer or Object name of FxOperator to connect. Default Value: Current selection. Note: If the current selection is not a valid FxOperator, an error occurs.
x | Float | Specifies the position of the FxOperator in X. Default Value: 0
y | Float | Specifies the position of the FxOperator in Y. Default Value: 0

### Examples

#### VBScript Example

    ' This example creates an FxTree, adds the FileInput operator
    ' to it, sets its position in X and Y, and prints the new positions.
    set oTree = CreateFxTree()
    set oFxOp = AddFxOp( oTree, "File Input" )
    ' Print the positions before updating
    printPositions( oFxOp )
    ' Move the operator icon upwards and to the left
    SetFxOpPos oFxOp, 143, 88
    ' Print the positions after updating
    printPositions( oFxOp )
    function printPositions( in_operator )
            ' There is no scripting command to get the positions
            ' of an FxOperator, but you can use the object model:
            Application.LogMessage "X and Y positions of the " _
                    & oFxOp.Name & " operator: " _
                    & oFxOp.PositionX & ", " _
                    & oFxOp.PositionY
    end function
    ' Output of above script:
    'INFO : "X and Y positions of the FileInput operator: 215, 146"
    'INFO : "X and Y positions of the FileInput operator: 143, 88"