Introduced
3.0
Description
Sets the position of an FxOperator in the FxTree.
Scripting Syntax
SetFxOpPos( [FxOp], [x], [y] )
Parameters
|
Parameter |
Type |
Description |
|
FxOp |
String or FxOperator |
Object pointer or Object name of FxOperator to connect. Default Value: Current selection. Note: If the current selection is not a valid FxOperator, an error occurs. |
|
x |
Specifies the position of the FxOperator in X. Default Value: 0 |
|
|
y |
Specifies the position of the FxOperator in Y. Default Value: 0 |
Examples
VBScript Example
' This example creates an FxTree, adds the FileInput operator ' to it, sets its position in X and Y, and prints the new positions. set oTree = CreateFxTree() set oFxOp = AddFxOp( oTree, "File Input" ) ' Print the positions before updating printPositions( oFxOp ) ' Move the operator icon upwards and to the left SetFxOpPos oFxOp, 143, 88 ' Print the positions after updating printPositions( oFxOp ) function printPositions( in_operator ) ' There is no scripting command to get the positions ' of an FxOperator, but you can use the object model: Application.LogMessage "X and Y positions of the " _ & oFxOp.Name & " operator: " _ & oFxOp.PositionX & ", " _ & oFxOp.PositionY end function ' Output of above script: 'INFO : "X and Y positions of the FileInput operator: 215, 146" 'INFO : "X and Y positions of the FileInput operator: 143, 88"
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